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Re: $$... parsing
Harald writes:
> ; f4 = fee fie foe foo
> ; name = f4
>
> Uh ... how to get foo starting from `name'? Only solution I see is
>
> ; echo <={let (x=$$name) result $x(4)}
> foo
Or more traditionally:
; list=$$name
; echo $list(4)
foo
> Maybe the parsing rules ought to be changed so that $$name(4) and
> $($name)(4) are parsed the same (and the latter the way I would have
> expected it to)?
This still might be a good idea.